已知x^2-xy=3,xy-y^2=-6,则x-y的值为?
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已知x^2-xy=3,xy-y^2=-6,则x-y的值为?已知x^2-xy=3,xy-y^2=-6,则x-y的值为?已知x^2-xy=3,xy-y^2=-6,则x-y的值为?x^2-xy=3xy-y^
已知x^2-xy=3,xy-y^2=-6,则x-y的值为?
已知x^2-xy=3,xy-y^2=-6,则x-y的值为?
已知x^2-xy=3,xy-y^2=-6,则x-y的值为?
x^2-xy=3
xy-y^2=-6
那么两式相减得到
x^2-2xy+y^2=(x-y)^2=9
所以x-y=正负3
x^2-xy=3
xy-y^2=-6
用上面的式子减去下面的式子得到:(x-y)^2=9;因此x-y的值是3或者-3
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