函数y=cos2x•sin(x＋π/3)－sin2x•cos(x＋π/3)的最小正周期T=

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函数y=cos2x•sin(x＋π/3)－sin2x•cos(x＋π/3)的最小正周期T=函数y=cos2x•sin(x＋π/3)－sin2x•cos(

函数y=cos2x•sin(x＋π/3)－sin2x•cos(x＋π/3)的最小正周期T=
函数y=cos2x•sin(x＋π/3)－sin2x•cos(x＋π/3)的最小正周期T=

函数y=cos2x•sin(x＋π/3)－sin2x•cos(x＋π/3)的最小正周期T=
左边是y=sin[(x+π/3)-2x]展开式.
所以
y=sin(-x+π/3)=-sin(x-π/3)
所以其最小正周期T=π