sin(α-π/3)=1/3 则cos(α+π/6)=

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sin(α-π/3)=1/3则cos(α+π/6)=sin(α-π/3)=1/3则cos(α+π/6)=sin(α-π/3)=1/3则cos(α+π/6)=sin(n/2+a)=cosa

sin(α-π/3)=1/3 则cos(α+π/6)=
sin(α-π/3)=1/3 则cos(α+π/6)=

sin(α-π/3)=1/3 则cos(α+π/6)=
sin(n/2+a)=cosa