1/2=1/1*2=1/1-1/2,1/6=1/2*3=1/2-1/3,1/12=1/3*4=1/3-1/4.计算1/(x-2)(x-3)-2/(x-1)(x-3)+1/(x-1)(x-2)
来源:学生作业帮助网 编辑:六六作业网 时间:2024/12/24 00:03:37
1/2=1/1*2=1/1-1/2,1/6=1/2*3=1/2-1/3,1/12=1/3*4=1/3-1/4.计算1/(x-2)(x-3)-2/(x-1)(x-3)+1/(x-1)(x-2)1/2=1
1/2=1/1*2=1/1-1/2,1/6=1/2*3=1/2-1/3,1/12=1/3*4=1/3-1/4.计算1/(x-2)(x-3)-2/(x-1)(x-3)+1/(x-1)(x-2)
1/2=1/1*2=1/1-1/2,1/6=1/2*3=1/2-1/3,1/12=1/3*4=1/3-1/4.
计算1/(x-2)(x-3)-2/(x-1)(x-3)+1/(x-1)(x-2)
1/2=1/1*2=1/1-1/2,1/6=1/2*3=1/2-1/3,1/12=1/3*4=1/3-1/4.计算1/(x-2)(x-3)-2/(x-1)(x-3)+1/(x-1)(x-2)
1
1/(x-3)(x-1)
按题设给的拆分再加减就可以了
1/(x-2)(x-3)=1/(x-3)-1/(x-2)
2/(x-1)(x-3)=1/(x-3)-1/(x-1)
1/(x-1)(x-2)=1/(x-2)-1/(x-1)
附带1/(x-m)(x-n)=1/(m-n) (1/(x-m)-1/(x-n))
因此原式的答案为0
123