因式分解2x^3+(2a+23)x^2+(10-7a)x+3a-11(a为常数)答案为(2x-1)(x^2+(a+12)+11-3a)

来源:学生作业帮助网 编辑:六六作业网 时间:2024/11/15 12:40:59
因式分解2x^3+(2a+23)x^2+(10-7a)x+3a-11(a为常数)答案为(2x-1)(x^2+(a+12)+11-3a)因式分解2x^3+(2a+23)x^2+(10-7a)x+3a-1

因式分解2x^3+(2a+23)x^2+(10-7a)x+3a-11(a为常数)答案为(2x-1)(x^2+(a+12)+11-3a)
因式分解2x^3+(2a+23)x^2+(10-7a)x+3a-11(a为常数)
答案为(2x-1)(x^2+(a+12)+11-3a)

因式分解2x^3+(2a+23)x^2+(10-7a)x+3a-11(a为常数)答案为(2x-1)(x^2+(a+12)+11-3a)
2x^3+(2a+23)x^2+(10-7a)x+3a-11
=2x^3-x^2+x^2+(2a+23)x^2+(10-7a)x+3a-11
=x^2*(2x-1)+(2a+24)x^2-(a+12)x+(a+12)x+(10-7a)x+3a-11
=x^2*(2x-1)+(a+12)x(2x-1)+(22-6a)x-(11-3a)
=x^2*(2x-1)+(a+12)x(2x-1)+(11-3a)(2x-1)
=(2x-1)(x^2+(a+12)+11-3a).