若x/2=y/3=z/4不等于0,求x+y+z/x+y-z的值

若x/2=y/3=z/4不等于0,求x+y+z/x+y-z的值
若x/2=y/3=z/4不等于0,求x+y+z/x+y-z的值

若x/2=y/3=z/4不等于0,求x+y+z/x+y-z的值
令a=x/2=y/3=z/4
则x=2a,y=3a,z=4a
所以原式=(2a+3a+4a)/(2a+3a-4a)
=9a/a
=9