求函数y=(x²-2x+2)/(x-1),(x

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求函数y=(x²-2x+2)/(x-1),(x求函数y=(x²-2x+2)/(x-1),(x求函数y=(x²-2x+2)/(x-1),(xy=(x²-2x+2)

求函数y=(x²-2x+2)/(x-1),(x
求函数y=(x²-2x+2)/(x-1),(x<1) 的最大值

求函数y=(x²-2x+2)/(x-1),(x
y=(x²-2x+2)/(x-1)
=(x-1)+1/(x-1)
=-[(1-x)+1/(1-x)]