已知x+2y=1,y+2z=2,2x+3z=3,则x+y+z的值为什么已知x+2y=1,y+2z=2,2x+3z=3,则x+y+z的值为 【 】A .0 B .1 C .2 D .3
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已知x+2y=1,y+2z=2,2x+3z=3,则x+y+z的值为什么已知x+2y=1,y+2z=2,2x+3z=3,则x+y+z的值为【】A.0B.1C.2D.3已知x+2y=1,y+2z=2,2x
已知x+2y=1,y+2z=2,2x+3z=3,则x+y+z的值为什么已知x+2y=1,y+2z=2,2x+3z=3,则x+y+z的值为 【 】A .0 B .1 C .2 D .3
已知x+2y=1,y+2z=2,2x+3z=3,则x+y+z的值为什么
已知x+2y=1,y+2z=2,2x+3z=3,则x+y+z的值为 【 】
A .0 B .1 C .2 D .3
已知x+2y=1,y+2z=2,2x+3z=3,则x+y+z的值为什么已知x+2y=1,y+2z=2,2x+3z=3,则x+y+z的值为 【 】A .0 B .1 C .2 D .3
三个方程相加得
3x+3y+3z=1+2+3
3x+3y+3z=6
∴x+y+z=2
选C
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答:2x+3z=3应该是2x+z=3吧?
x+2y=1…………(1)
y+2z=2………………(2)
2x+z=3…………(3)
上面三式相加得:
3x+3y+3z=6
x+y+z=2
选择C同样谢谢啦~你的题目都错误,他这样解答......大标题虽然错了,可是内容还是正确的呀.连这点小错误都不敢承认啊.....标题和内容都错误!内容哪里有错...
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答:2x+3z=3应该是2x+z=3吧?
x+2y=1…………(1)
y+2z=2………………(2)
2x+z=3…………(3)
上面三式相加得:
3x+3y+3z=6
x+y+z=2
选择C
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