(1)求证;sinαcosα/sin²α-cos²α=-1/2tan2α(2)求sin50°(1+√3tan10°)的值
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(1)求证;sinαcosα/sin²α-cos²α=-1/2tan2α(2)求sin50°(1+√3tan10°)的值
(1)求证;sinαcosα/sin²α-cos²α=-1/2tan2α(2)求sin50°(1+√3tan10°)的值
(1)求证;sinαcosα/sin²α-cos²α=-1/2tan2α(2)求sin50°(1+√3tan10°)的值
-1/2tan2α
=- tana/(1-tan^a)
=-cos^a*tana/(cos^a-sin^a)
=sinαcosα/sin²α-cos²α
右边=左边
∴sinαcosα/sin²α-cos²α=-1/2tan2α
(2)求
sin50°(1+√3tan10°)
=sin50°(cos10°+√3sin10°)/cos10°
=2sin50°(1/2 cos10°+√3/2 sin10°)/cos10°
=2sin50°sin40°/cos10°
=2cos40°sin40°/cos10°
=sin80°/cos10°
=1
你好
sinαcosα/(sin²α-cos²α)
=1/2*(2sinαcosα)/[-(cos²α-sin²α)]
=-1/2sin2α/cos2α
=-1/2tan2α
sin50°(1+√3tan10°)
=sin50°(1+√3sin10°/cos10°)
=cos(9...
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你好
sinαcosα/(sin²α-cos²α)
=1/2*(2sinαcosα)/[-(cos²α-sin²α)]
=-1/2sin2α/cos2α
=-1/2tan2α
sin50°(1+√3tan10°)
=sin50°(1+√3sin10°/cos10°)
=cos(90°-50°)(cos10°+√3sin10°)/cos10°
=cos40°*2(1/2cos10°+√3/2sin10°)/cos10°
=2cos40°(sin30°cos10°+cos30°sin10°)/cos10°
=2cos40°sin(30°+10°)/cos10°
=2cos40°sin40°/cos10°
=sin80°/cos10°
=cos10°/cos10°
=1
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证明及解
(1)证明:
sinαcosα/sin²α-cos²α
分子分母同时除以cos²α
=tanα/(tan²α-1)
=(-1/2)*[2tanα/(1-tan²α)]
=(-1/2) tan2α
另法:也可以从右边证明
即展开tan2α
tan2α=2t...
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证明及解
(1)证明:
sinαcosα/sin²α-cos²α
分子分母同时除以cos²α
=tanα/(tan²α-1)
=(-1/2)*[2tanα/(1-tan²α)]
=(-1/2) tan2α
另法:也可以从右边证明
即展开tan2α
tan2α=2tanα/(1-tan²α)
然后,切化弦即可得到左边的结果。
(2)
sin50°(1+√3tan10°)
=(1+√3tan10°)sin50°
=sin50°(1+√3sin10°/cos10°)
=sin50°(cos10°+√3sin10°)/cos10°
=2sin50°[(√3/2)sin10°+(1/2)cos10°]/cos10°
=2sin50°(sin10°cos30°+cos10°sin30°)/cos10°
=2sin50°*sin(10°+30°)/cos10°
=2sin50*sin40°/cos10°
=2cos40°sin40°/cos10°
=sin80°/cos10°
=1
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(1)sinαcosα/sin²α-cos²α
=1/2sin2a/(-cos2a)
=-1/2*tan2a
(2)解:sin50°(1+√3tan10°)
=sin50°(cos10°/cos10°+√3sin10°/cos10°)
=sin50°(cos10°+√3sin10°)/cos10°
=sin50°2(1/2cos1...
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(1)sinαcosα/sin²α-cos²α
=1/2sin2a/(-cos2a)
=-1/2*tan2a
(2)解:sin50°(1+√3tan10°)
=sin50°(cos10°/cos10°+√3sin10°/cos10°)
=sin50°(cos10°+√3sin10°)/cos10°
=sin50°2(1/2cos10°+√3/2sin10°)/cos10°
=sin50°2(sin30°cos10°+cos30°sin10°)/cos10°
=sin50°2(sin(30°+10°))/cos10°
=sin50°2sin40°/cos10°
=2cos40°sin40°/cos10°
=sin80°/cos10°
=cos10°/cos10°
=1=1
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