若(x-5y-16)2+｜5y-5x-4｜=0,则a= b=

若(x*x+y*y)(x*x+y*y)-4x*x*y*y=0,求代数式(x*x+5xy+y*y)/(x*x+2xy+y*y)的值 4x+2y-5x-y 因式分解(x-2y)(x-3y)+(x-4y)(x-5y)+（x-3y)(x-5y)+(x-2y)(x-4y) 若x*x+4*y*y+2*x-4*y+2=0,求5*x*x+16*y*y的算术平方跟 5/4(x+y)(-x-y)^3*[-4/3(x-y)]*[-3/5(y-x)^2] [(2x+y)^2-(x+y)(x-4y)-5y^2]除以2x (2x-y)(3x-4y)-2(x-y)(2x-5y)简便运算 3(x+y)+2(x-y)=36 4(x+y)-5(x-y)=2 4(x-y)-3(x-y)=9 5(x-y)+2(x-y)=11 3(x+y)-4(x-y)=11,2(x-y)+5(x+y)=27 x*x+2x+y*y-4y+5=0 x= y= 5x^3y(x-y)^3-10x^4y^3(y-x)^2因式分解 5x^3y(x-y)^3-10x^4y^3(y-x)^2 5X^3Y(X-Y)-10X^4Y^3(Y-X)^2因式分解 （x-y）^3×（y-x）^4+（x-y）^2×（y-x）^5 计算(x^8-x^7y+x^5y^3-x^4y^4+x^3y^5-x^y^7+y^8)(x^2+xy+y^2) 先化简再求值(x-y)(x-2y)+(x-2y)(x-3y)-2(x-3y)(x-4y) x=4 y=5 已知x*x+4x+y*y-2y+5=0,则x*x+y*y=?