若(x-5y-16)2+|5y-5x-4|=0,则a= b=
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若(x-5y-16)2+|5y-5x-4|=0,则a=b=若(x-5y-16)2+|5y-5x-4|=0,则a=b=若(x-5y-16)2+|5y-5x-4|=0,则a=b=(x-5y-16)2+|5
若(x-5y-16)2+|5y-5x-4|=0,则a= b=
若(x-5y-16)2+|5y-5x-4|=0,则a= b=
若(x-5y-16)2+|5y-5x-4|=0,则a= b=
(x-5y-16)2+|5y-5x-4|=0
则:
x-5y=16
5y-5x=4
两式相加得:
-4x=20
x=-5
代入上式得:
5y=4-25=-21
y=-21/5
所以:x=-5;y=-21/5
若(x-5y-16)2+|5y-5x-4|=0,则
5-5y=16
5y-5x=4
5-5x=20
x=-3
y=-2.2
(x-5y-16)2+|5y-5x-4|=0
解:x-5y=16
5y-5x=4
两式相加得:
-4x=20
x-5
5y=4-25=-21
y=-21/5
答:x=-5;y=-21/5
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