1/4x^2y-3x^2+3/4x^2y+2x^2合并同类项
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1/4x^2y-3x^2+3/4x^2y+2x^2合并同类项1/4x^2y-3x^2+3/4x^2y+2x^2合并同类项1/4x^2y-3x^2+3/4x^2y+2x^2合并同类项1/4x^2y-3x
1/4x^2y-3x^2+3/4x^2y+2x^2合并同类项
1/4x^2y-3x^2+3/4x^2y+2x^2
合并同类项
1/4x^2y-3x^2+3/4x^2y+2x^2合并同类项
1/4x^2y-3x^2+3/4x^2y+2x^2
=1/4x^2y+3/4x^2y+2x^2-3x^2
=x^2y-x^2
1/4x^2y-3x^2+3/4x^2y+2x^2
原式=(1/4+3/4)x^2y-x^2
=x^2y-x^2
x²/xy-x/y 3x/4x+y - x-2y/4x+y (1-y/y+x)÷x/y²-x²
{3(x+y)-4(x-y)=4 {x+y/2 + x-y/6=1
(x-y) (x-2y)+(x+2y) (x-3y)-2(x-3y) (x-4y)=
(x+3y-4)(2x-y)
计算(2x-3y)(x+4y)-(3x+y)(x-2y)(2x-3y)(x+4y)-(3x+y)(x-2y)
1/(x-y)+1/(x+y)+2x/(x^2+y^2)+4x^3/(x^4+y^4)化简
因式分解(x-2y)(x-3y)+(x-4y)(x-5y)+(x-3y)(x-5y)+(x-2y)(x-4y)
x+y+2(-x-y+1)=3(1-y-x)-4-(y+x-1),x+y=?
先化简 再求值 (2x-y)(y+x)-(x-2y)(2y+x)-(-3y+x)^2其(√x+1)+y^2+4=-4y
计算:1/(x-y)-1/(x+y)-2y/(x^2+y^2)-4y^3/(x^4+y^4)-8x^7/(x^8+y^8)
化简[(3x+4y)^2-(2x+y)(2x-y)+(-x+y)(5x-y)]除以-2y,其中x=-1,y=1
已知x-y=1,求[(x+2y)^2+(2x+y)(x-4y)-3(x+y)(x-y)]除以y的值大神们帮帮忙
已知x-y=1,求[(x+2y)²+(2x+y)(x-4y)-3(x+y)(x-y)]÷y的值
(2x+y)(2x-3y)+x(2y+y) 2a(x-y)-4b(x-y)
(x/x+y +2y/x+y)乘以xy/ x+2y除以(1/x+1/y)(2)(3x^2/4y)^2乘以2y/3x+ x^2/2y^2除以2y^2/x
9y=3x-(x-1),4(x+y)-(2x+4)=8y
4x(x-y)-(2x-3y)(2x-3y) x=1 y=-1
[(y-2x)(-2x-y)+4(x-2y)平方]/3y,其中x=1,y=-3