若(2x-2y)^2+|5x-7y-2|=0,则x+2y的值为?急,
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若(2x-2y)^2+|5x-7y-2|=0,则x+2y的值为?急,若(2x-2y)^2+|5x-7y-2|=0,则x+2y的值为?急,若(2x-2y)^2+|5x-7y-2|=0,则x+2y的值为?
若(2x-2y)^2+|5x-7y-2|=0,则x+2y的值为?急,
若(2x-2y)^2+|5x-7y-2|=0,则x+2y的值为?
急,
若(2x-2y)^2+|5x-7y-2|=0,则x+2y的值为?急,
解
(2x-2y)^2+|5x-7y-2|=0
∴2x-2y=0,①
5x-7y-2=0 ②
①变为x=y代入②得:
5x-7x-2=0
-2x=2
∴x=y=-1
∴x+2y=-1-2=-3
解析
因为绝对值大于等于0
所以
2(x-y)=0
x=y
5x-7y-2=0
x=y=-1
所以x+2y=-1+-2=-3
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