已知x/xˆ2-x+1 =7,求xˆ2/xˆ4+xˆ2+1（用倒数法计算最好）!

已知x/xˆ2-x+1 =7,求xˆ2/xˆ4+xˆ2+1（用倒数法计算最好）!
已知x/xˆ2-x+1 =7,求xˆ2/xˆ4+xˆ2+1（用倒数法计算最好）!

已知x/xˆ2-x+1 =7,求xˆ2/xˆ4+xˆ2+1（用倒数法计算最好）!
x/(xˆ2-x+1 )=7 吗?
x-1+1/x=1/7 x+1/x=8/7
xˆ2/(xˆ4+xˆ2+1)=1/(x²+1+1/x²）=1/[(x+1/x)²+1] = 1/[(8/7)²+1]=49/113

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x/xˆ2-x+1 =7
1/(x-1+(1/x))=7
x+(1/x)=8/7
xˆ2/xˆ4+xˆ2+1
=1/(x²+1+(1/x²))
=1/((x+(1/x))²-1)