已知x/2=y/3=z/4求2x+3y+4z/5x-2y

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已知x/2=y/3=z/4求2x+3y+4z/5x-2y已知x/2=y/3=z/4求2x+3y+4z/5x-2y已知x/2=y/3=z/4求2x+3y+4z/5x-2y令x/2=y/3=z/4=k则x

已知x/2=y/3=z/4求2x+3y+4z/5x-2y
已知x/2=y/3=z/4求2x+3y+4z/5x-2y

已知x/2=y/3=z/4求2x+3y+4z/5x-2y
令x/2=y/3=z/4=k
则x=2k,y=3k,z=4k
所以(2x+3y+4z)/(5x-2y)
=(4k+9k+16k)/(10k-6k)
=29k/4k
=29/4

设x/2=k
∴x=2k,
则y=3k,z=4k
∴(2x+3y+4z)/(5x-2y)
=(4k+9k+16k)/(10k-6k)
=29k/4k
=29/4