数学题(1)38.5²-36.5²(2)(2x-3y-1)(2x+3y+1)(3+1)(3^2+1)(3^4+1)(3^8+1)(3^16+1)抱歉是第一题38.5²-36.5² 第二题(2x-3y-1)(2x+3y+1)第三题(3+1)(3^2+1)(3^4+1)(3^8+1)(3^16+1)第四题200

来源:学生作业帮助网 编辑:六六作业网 时间:2024/11/25 01:58:07
数学题(1)38.5²-36.5²(2)(2x-3y-1)(2x+3y+1)(3+1)(3^2+1)(3^4+1)(3^8+1)(3^16+1)抱歉是第一题38.5²-3

数学题(1)38.5²-36.5²(2)(2x-3y-1)(2x+3y+1)(3+1)(3^2+1)(3^4+1)(3^8+1)(3^16+1)抱歉是第一题38.5²-36.5² 第二题(2x-3y-1)(2x+3y+1)第三题(3+1)(3^2+1)(3^4+1)(3^8+1)(3^16+1)第四题200
数学题(1)38.5²-36.5²(2)(2x-3y-1)(2x+3y+1)(3+1)(3^2+1)(3^4+1)(3^8+1)(3^16+1)
抱歉是第一题38.5²-36.5² 第二题(2x-3y-1)(2x+3y+1)第三题(3+1)(3^2+1)(3^4+1)(3^8+1)(3^16+1)第四题2003^2-3001^2

数学题(1)38.5²-36.5²(2)(2x-3y-1)(2x+3y+1)(3+1)(3^2+1)(3^4+1)(3^8+1)(3^16+1)抱歉是第一题38.5²-36.5² 第二题(2x-3y-1)(2x+3y+1)第三题(3+1)(3^2+1)(3^4+1)(3^8+1)(3^16+1)第四题200
1.
38.5^2-36.5^2
=(38.5+36.5)(38.5-36.5)
=75*2
=150
2.
(2x-3y-1)(2x+3y+1)
=[2x-(3y+1)][2x+(3y+1)]
=4x^2-(3y+1)^2
=4x^2-(9y^2+6y+1)
=4x^2-9y^2-6y-1
3.
(3+1)(3^2+1)(3^4+1)(3^8+1)(3^16+1)
=(1/2)(3-1)(3+1)(3^2+1)(3^4+1)(3^8+1)(3^16+1)
=(1/2)(3^2-1)(3^2+1)(3^4+1)(3^8+1)(3^16+1)
=(1/2)(3^4-1)(3^4+1)(3^8+1)(3^16+1)
=(1/2)(3^8-1)(3^8+1)(3^16+1)
=(1/2)(3^16-1)(3^16+1)
=(1/2)(3^32-1)
=3^32/2-1/2

1:150
2:4x^2-9y^2-6y-1
3:9.265100944×10的14次方

(1).38.5²-36.5²=(38.5+36.5)(38.5-36.5)=75*2=150
(2).(2x-3y-1)(2x+3y+1)=(2x-(3y+1))(2x+(3y+1))=(2x)²-(3y+1)²=4x²-9y²-6y+1
(3).(3+1)(3^2+1)(3^4+1)(3^8+1)(3^16+1)

全部展开

(1).38.5²-36.5²=(38.5+36.5)(38.5-36.5)=75*2=150
(2).(2x-3y-1)(2x+3y+1)=(2x-(3y+1))(2x+(3y+1))=(2x)²-(3y+1)²=4x²-9y²-6y+1
(3).(3+1)(3^2+1)(3^4+1)(3^8+1)(3^16+1)
=0.5(3-1)(3+1)(3^2+1)(3^4+1)(3^8+1)(3^16+1)
=0.5(3²-1)(3²+1)(3^4+1)(3^8+1)(3^16+1)
=0.5(3^4-1)(3^4+1)(3^8+1)(3^16+1)
=0.5(3^8-1)(3^8+1)(3^16+1)
=0.5(3^16-1)(3^16+1)
=0.5(3^32-1)

收起

(38.5-36.5)*(38.5+36.5)=150
=4x²-(3y+1)²=4x²-9y²-6y-1
第三题我只会直接用计算机算

1、(38,5-36.5)*(38.5+36.5)=150
2、[2x-(3y+1)]*[2x+(3y+1)]=4x^2-(3y+1)^2
3、92651009442520