public String removeType(String sou){String result=sou;if(sou.indexOf("^^")>0){result=sou.substring(0,sou.indexOf("^^"));}return result;}

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publicStringremoveType(Stringsou){Stringresult=sou;if(sou.indexOf("^^")>0){result=sou.substring(0,so

public String removeType(String sou){String result=sou;if(sou.indexOf("^^")>0){result=sou.substring(0,sou.indexOf("^^"));}return result;}
public String removeType(String sou){
String result=sou;
if(sou.indexOf("^^")>0){
result=sou.substring(0,sou.indexOf("^^"));
}
return result;
}

public String removeType(String sou){String result=sou;if(sou.indexOf("^^")>0){result=sou.substring(0,sou.indexOf("^^"));}return result;}
if(sou.indexOf("^^")>0)---------》就是说返回sou这个字符串第一次出现^^的位置n:例如:
"sfjkd^^fjk".indexOf("^^")就为5,如果没有匹配的如"sfjkdfjk".indexOf("^^")则会返回-1,此条件就不成立,下面无法执行;
String result=sou;-------》就是把形参赋给实参result;
result=sou.substring(0,sou.indexOf("^^"));-------》就是条件成立时,sou这个字符串截取0到n的字符,把得到的字符串赋给result;
最后就是返回一个值了呀

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