a²-2ab+b²+2（a-b）+1=0,求a-b的值

a²-2ab+b²+2（a-b）+1=0,求a-b的值
a²-2ab+b²+2（a-b）+1=0,求a-b的值

a²-2ab+b²+2（a-b）+1=0,求a-b的值
a²-2ab+b²+2（a-b）+1=0
(a-b)²+2(a-b)+1=0
[(a-b)+1]²=0
所以a-b+1=0
a-b=-1

a²-2ab+b²+2(a-b)+1=0 (a-b)²+2（a-b）+1=0 设a-b=X x²+2x+1=0 (x+1)²=0 x=-1 得a-b=-1,回答不易，请采纳！

因为：a²-2ab+b²+2（a-b）+1=0
变形为：（a-b）²+2（a-b）+1=0
也就是：（a-b+1）²=0
所以：a-b=-1