1+(1/1+2)+(1/1+2+3)+...+(1/1+2+3+...100)=?

1+(1/1+2)+(1/1+2+3)+...+(1/1+2+3+...100)=?
1+(1/1+2)+(1/1+2+3)+...+(1/1+2+3+...100)=?

1+(1/1+2)+(1/1+2+3)+...+(1/1+2+3+...100)=?
1+1/(1+2)+1/(1+2+3)+...+1/(1+2+3+...100)
=1+1/3+1/6+1/10+...+1/5050
=2/2+2/6+2/12+2/20+...+2/10100
=2/(1×2)+2/(2×3)+2/(3×4)+2/(4×5)+...+2/(100×101)
=2(1/1-1/2)+2(1/2-1/3)+2(1/3-1/4)+2(1/4-1/5)+...+2(1/100-1/101)
=2(1-1/2+1/2-1/3+1/3-1/4+1/4-1/5+...+1/100-1/101)
=2(1-1/101)
=200/101

an=1/(n(n+1)/2)=2/(n(n+1))=2((1/n)-(1/(n+1))
1+(1/1+2)+(1/1+2+3)+...+(1/1+2+3+...100)
=2((1/1)-(1/2)+(1/2)-(1/3)+...+(1/100)-(1/101))
=2(1-(1/101))
=200/101

由1/(1+2+…+n)=2/n(n+1)=2(1/n-1/n+1)，故得
1+(1/1+2)+(1/1+2+3)+...+(1/1+2+3+...100)
=2(1-1/2)+ 2(1/2-1/3)+ 2(1/3-1/4)+…+2(1/100-1/101)
=2(1-1/101)=200/101

你打错咯。。
应该系1+1/(1+2)+1/(1+2+3)+...+1/(1+2+3+...100)
解析1+1/(1+2)+1/(1+2+3)+...+1/(1+2+3+...100)
=1+1/3+1/6+1/10+...+1/5050
=2/2+2/6+2/12+2/20+...+2/10100
=2/(1×2)+2/(2×3)+2/(3×4)+2/(...

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你打错咯。。
应该系1+1/(1+2)+1/(1+2+3)+...+1/(1+2+3+...100)
解析1+1/(1+2)+1/(1+2+3)+...+1/(1+2+3+...100)
=1+1/3+1/6+1/10+...+1/5050
=2/2+2/6+2/12+2/20+...+2/10100
=2/(1×2)+2/(2×3)+2/(3×4)+2/(4×5)+...+2/(100×101)
=2(1/1-1/2)+2(1/2-1/3)+2(1/3-1/4)+2(1/4-1/5)+...+2(1/100-1/101)
=2(1-1/2+1/2-1/3+1/3-1/4+1/4-1/5+...+1/100-1/101)
=2(1-1/101)
=200/101

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