已知x2+y2-2x+6y+10=0,则x+y的值为?

已知x2+y2-2x+6y+10=0,则x+y的值为?
已知x2+y2-2x+6y+10=0,则x+y的值为?

已知x2+y2-2x+6y+10=0,则x+y的值为?
即(x²-2x+1)+(y²+6u+9)=0
(x-1)²+(y+3)²=0
所以x-1=y+3=0
x=1,y=-3
所以x+y=-2

x2+y2-2x+6y+10=0
(x-1)²+(y+3)²=0
x=1,y=-3
x+y=1-3=-2

x2+y2-2x+6y+10=0
（x-1)²+（y+3）²=0
x=1 y=-3
x+y=-2

-2
x2+y2-2x+6y+10=0可化为(x-1)2+(y+3)2=0
(x-1)2>=0,(y+3)2>=0 又因为(x-1)2+(y+3)2=0
所以x-1=0 y+3=0所以x=1 y=-3