求[(x-2y)^2-(2x+y)(2x-y)+(3x-y)(x+y)]/2的值 已知4y^2+4y+|x-1|=0
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求[(x-2y)^2-(2x+y)(2x-y)+(3x-y)(x+y)]/2的值已知4y^2+4y+|x-1|=0求[(x-2y)^2-(2x+y)(2x-y)+(3x-y)(x+y)]/2的值已知4
求[(x-2y)^2-(2x+y)(2x-y)+(3x-y)(x+y)]/2的值 已知4y^2+4y+|x-1|=0
求[(x-2y)^2-(2x+y)(2x-y)+(3x-y)(x+y)]/2的值 已知4y^2+4y+|x-1|=0
求[(x-2y)^2-(2x+y)(2x-y)+(3x-y)(x+y)]/2的值 已知4y^2+4y+|x-1|=0
应该是4y^2+4y+1+|x-1|=0
(2y+1)²+|x-1|=0
所以2y+1=0,x-1=0
x=1,y=-1/2
原式=(x²-4xy+4y²-4x²+y²+3x²+2xy-y²)/2
=(-2xy+4y²)/2
=-xy+2y²
=1/2+1
=3/2
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