已知:如图AB=AC,AD=AE.AB,DC相交于点M,AC,BE相交于点N,
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已知:如图AB=AC,AD=AE.AB,DC相交于点M,AC,BE相交于点N,已知:如图AB=AC,AD=AE.AB,DC相交于点M,AC,BE相交于点N,已知:如图AB=AC,AD=AE.AB,DC
已知:如图AB=AC,AD=AE.AB,DC相交于点M,AC,BE相交于点N,
已知:如图AB=AC,AD=AE.AB,DC相交于点M,AC,BE相交于点N,
已知:如图AB=AC,AD=AE.AB,DC相交于点M,AC,BE相交于点N,
角DAB=角EAC,所以角DAC=角EAB,所以三角形ADC全等于 三角形AEB,所以 AM=AN;
OVER
答案补充角DAB=角EAC,所以角DAC=角EAB(边角边(SAS))
答案补充角DAB=角EAC,所以角DAC=角EAB,AB=AC,AD=AE (边角边
图在哪?
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