1、(3b-2c)+[-4a-(c-3a)]-(3b-c)2、-a^n-(-5)a^n-1-2(a^n-1-3a^n)
来源:学生作业帮助网 编辑:六六作业网 时间:2024/11/16 14:24:44
1、(3b-2c)+[-4a-(c-3a)]-(3b-c)2、-a^n-(-5)a^n-1-2(a^n-1-3a^n)1、(3b-2c)+[-4a-(c-3a)]-(3b-c)2、-a^n-(-5)a
1、(3b-2c)+[-4a-(c-3a)]-(3b-c)2、-a^n-(-5)a^n-1-2(a^n-1-3a^n)
1、(3b-2c)+[-4a-(c-3a)]-(3b-c)
2、-a^n-(-5)a^n-1-2(a^n-1-3a^n)
1、(3b-2c)+[-4a-(c-3a)]-(3b-c)2、-a^n-(-5)a^n-1-2(a^n-1-3a^n)
1、(3b-2c)+[-4a-(c-3a)]-(3b-c)
=3b-2c+[-4a-c+3a]-3b+c
=3b-2c-4a-c+3a-3b+c
=-4a+3a+3b-3b-2c-c+c
=-a-2c
2 -a^n-(-5)a^n-1-2(a^n-1-3a^n)
= -a^n+5a^n-1-2a^n+2+6a^n
=-a^n+5a^n-2a^n+6a^n-1+2
=8a^n+1
3a-c=4a+2b-c=a+b+c a:b:c
已知A=a*a+b*b-c*c,B=-4a*a+2b*b+3c*c,且A+B+C=0.求(1)多项式C
已知:(a-b)(b-c)(c-a)/(a+b)(b+c)(c+a)=5/132,求a/(a+b)+b/(b+c)+c/(c+a)的值!(请尽快,我有急用,a/(a+b)+b/(b+c)+c/(c+a)=1/2[(a-b)/(a+b)+(b-c)/(b+c)+(c-a)/(c+a)]+3/2 (a-b)/(a+b)+(b-c)/(b+c)+(c-a)/(c+a) 没有错吧...
(a-b+c/a+b-c)-(a-2b+3c/b-c+a)+(b-2c/c-a-b)
a,b,c∈R+,证(a+b+c)(1/a+1/b+1/c)>=9证1.(a+b+c)(1/a+1/b+1/c)>=92.(a+b+c)(1/a+b +1/b+c +1/c+a)>=9/23.a/b+c +b/c+a +c/a+b>=3/2
-(-3a-2b+2c)-{-a+[4a-(a-b-c)-3a]+2c}
(a-b)(b-c)(c-a)/(b-a)(a-c)2(c-b)3
2a(a+b-c)-3b(a+b-c)+5c(c-a-b)
(a-2b分之2+a-b分之1)*(3a-4b)(a+b)分之a-2b(b-c)(c-a)分之a+b-(a-b)(a-c)分之b+c-(a-b)(c-b)分之c+a
化简:5(a-2b+c)-4(-a+b-c)+4(3a-2b)
5a-{-3b+[6c-2a-(a-c)]}-[9a-(7b+c)]
(a+b-c)^5(a-b-c)^2(c-a-b)^4(c+b-a)^3 计算
(1)化简:5a+(4b-c)-3(a+3b-2c)
(1)化简:5a+(4b-c)-3(a+3b-2c)
若有理数a、b、c满足:(a-1)指数2+(2a-b)指数4+|a-3c|=0,求a+b+c的值
若有理数a,b,c满足:(a-1)+(2a-b)4的平方+/a-3c/=0,求a+b+c的值
A:B二3:4 B:C=2:1 A:C二():()
实数abc满足a+b+c=1,且a^2+b^2+c^2=a^3+b^3+c^3,则a^2(b+c)+b^2(c+a)+c^2(a+b)=?;a^3+b^3+c^3+a^2+b^2+c^2+4ab+4bc+4ac=