y=(3x-1)/(x+1) (x>=5)值域 y=x-√(1-2x)值域
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y=(3x-1)/(x+1)(x>=5)值域y=x-√(1-2x)值域y=(3x-1)/(x+1)(x>=5)值域y=x-√(1-2x)值域y=(3x-1)/(x+1)(x>=5)值域y=x-√(1-
y=(3x-1)/(x+1) (x>=5)值域 y=x-√(1-2x)值域
y=(3x-1)/(x+1) (x>=5)值域 y=x-√(1-2x)值域
y=(3x-1)/(x+1) (x>=5)值域 y=x-√(1-2x)值域
1.分离变量.Y∈[7/3,3)
2.设t=根号(1-2x).Y∈(负无穷,0.5]
1.y=3-4/(x+1),由于x>=5,所以 y>=7/3
2. 用deta 法算 y<=1
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