sin(x/2) - cos(x/2)=1 求x的解集?
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sin(x/2)-cos(x/2)=1求x的解集?sin(x/2)-cos(x/2)=1求x的解集?sin(x/2)-cos(x/2)=1求x的解集?sin(x/2)-cos(x/2)=根号2倍sin
sin(x/2) - cos(x/2)=1 求x的解集?
sin(x/2) - cos(x/2)=1 求x的解集?
sin(x/2) - cos(x/2)=1 求x的解集?
sin(x/2) - cos(x/2)=根号2倍sin(x/2- pai/4)=1
则sin(x/2- pai/4)=根号2/2
故x/2- pai/4=pai/4 + 2k*pai,或x/2- pai/4=3*pai/4 + 2k*pai
,因此
x=(4k+1)pai,或x=(4k+2)pai,也即4k*pai,
k属于Z
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