已知(2x+2y+1)(2x+2y-1)=3 则x+y=___如题

已知x+y=a,2x-y=-2a,求[（x/y-y/x)/(x+y)-x(1/x-1/y)]/[(x+1)/y]的值 已知x-y=1,求[(x+2y)^2+(2x+y)(x-4y)-3(x+y)(x-y)]除以y的值大神们帮帮忙 已知:【(x²+y²)-(x-y)²+2y(x-y)】/4y=1,求4x/4x²-y²-1/2x+y 已知x-y=1,求[(x+2y)²+(2x+y)(x-4y)-3(x+y)(x-y)]÷y的值 已知：2x+y=6,x-3y=1 求7y(x-3y)(x-3y)-2(3y-x)(3y-x) 已知x,y满足约束条件：x-y+1>=0,x+y-2>=0,x [(-x-y)(-x+y)-(x+y)^2-x(y-y^2)}÷1/2y 已知x=2+根号3,y=2-根号3,计算代数式(x+y/x-y-x-y/x+y)乘以(1/x^2-1/y^2) 已知x/y=1/2,求2x/(x²-2xy+y² )* (x²-y²/x+y)+2y/x-y 已知x/y=1/2,求2x/(x²-2xy+y² )* (x²-y²/x+y)+2y/x-y 已知((x+y)平方-(x-y)的平方-2y(x+2分之1y))除以4y=1 已知x^2+y^2-8x+12y+52=0 ,求1/2x-1/x-y(x-y/2x-x^2+y^2) 已知x^2+y^2-8x+12y+52=0 ,求1/2x-1/x-y(x-y/2x-x^2+y^2) mathematica软件,已知y[x],Y=f1(x),X(x)=f2(x),如何plot Y[X]?y[x_] := x + 9.81/2*x*xk=1X[x] = x - k*y'[x]/(1 + (y'[x])^2)^0.5Y[x] = y[x] + k/(1 + (y'[x])^2)^0.5Plot[{y[x],Y[X],},{x,0,2}] 已知 x-2y=-2 求(2y-x)平方-2x+4y-1 已知(x+y)^2-2x+2y+1=0,则(x+y)^999= 已知x平方+y平方+2xy+1=2x+2y,求x+y 已知x平方+y平方-2xy-2x-2y=-1,求x+y