x+y=3,xy=-2,求x(x+y)(x-y)-x{(x+y)的2次方} \(≥▽≤)/~

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x+y=3,xy=-2,求x(x+y)(x-y)-x{(x+y)的2次方}\(≥▽≤)/~x+y=3,xy=-2,求x(x+y)(x-y)-x{(x+y)的2次方}\(≥▽≤)/~x+y=3,xy=-

x+y=3,xy=-2,求x(x+y)(x-y)-x{(x+y)的2次方} \(≥▽≤)/~
x+y=3,xy=-2,求x(x+y)(x-y)-x{(x+y)的2次方} \(≥▽≤)/~

x+y=3,xy=-2,求x(x+y)(x-y)-x{(x+y)的2次方} \(≥▽≤)/~
原式=-2xy(x+y)
=-2(-2)*3
=12
(原式=x(x+y)[x-y-(x+y)]
=x(x+y)(-2y)
=-2xy(x+y) )

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