[(3x^-1*y^-2)^2]*(x^2*y^2)]/(3xy^3)^-2分解dui
来源:学生作业帮助网 编辑:六六作业网 时间:2024/11/24 12:21:10
[(3x^-1*y^-2)^2]*(x^2*y^2)]/(3xy^3)^-2分解dui[(3x^-1*y^-2)^2]*(x^2*y^2)]/(3xy^3)^-2分解dui[(3x^-1*y^-2)^
[(3x^-1*y^-2)^2]*(x^2*y^2)]/(3xy^3)^-2分解dui
[(3x^-1*y^-2)^2]*(x^2*y^2)]/(3xy^3)^-2
分解
dui
[(3x^-1*y^-2)^2]*(x^2*y^2)]/(3xy^3)^-2分解dui
是化简吧?下面的题吗?
x²/xy-x/y 3x/4x+y - x-2y/4x+y (1-y/y+x)÷x/y²-x²
化简 3x(x^2-x-1)-(x+1)(3x^-x) X^3(x-y)+x(y-x)
若2/x-1/y=3,求[y/x-y/x-y(x-y/x-x+y)]/x-2y/x的值
x(x-y)2-(y-x)3
[2/3x-2/x+y(x+y/3x-x-y)]/x-y/x
化简:{2/3x-2/(x+y)[(x+y)/3x-x-y]}/(x+y)/x
计算2/3x-2/x+y(x+y/3x-x-y)/x-y/x
化简3x-2/(x+y)[(x+y)/3x-x-y]÷(x-y)/x
(3x-y)^2+(3x+y)(3x-y),x=1,y=-2
二元一次方程 :2(x+y)-(x-y)=3 (x+y)-2(x-y)=1
(x-y)/(x+y)=3求( 3x-2y-1)/(x+y-5)
2(x+y)-3(x-y)=1 6(x+y)+(x-y)=51
{3(x+y)-4(x-y)=4 {x+y/2 + x-y/6=1
变量x,y满足约束条件,x+y>=3,x-y>=-1,2x-y
(Y-X)^3*(X-Y)^m+(X-Y) ^m+1*(Y-X)^2
(x-y)^2+(x+y)(x-y) 其中 X =3 Y=-1
函数,y=3x/(x^2+x+1) ,x
函数y=3x/(x^2+x+1) (x