把(X-Y)和(X+Y)各看作一个字母因式,合并同类项3(X+Y)²-(X-Y)+2(X+Y)²+(X-Y)-5(X+Y)²=

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把(X-Y)和(X+Y)各看作一个字母因式,合并同类项3(X+Y)²-(X-Y)+2(X+Y)²+(X-Y)-5(X+Y)²=把(X-Y)和(X+Y)各看作一个字母因式,

把(X-Y)和(X+Y)各看作一个字母因式,合并同类项3(X+Y)²-(X-Y)+2(X+Y)²+(X-Y)-5(X+Y)²=
把(X-Y)和(X+Y)各看作一个字母因式,合并同类项3(X+Y)²-(X-Y)+2(X+Y)²+(X-Y)-5(X+Y)²=

把(X-Y)和(X+Y)各看作一个字母因式,合并同类项3(X+Y)²-(X-Y)+2(X+Y)²+(X-Y)-5(X+Y)²=
3(X+Y)²-(X-Y)+2(X+Y)²+(X-Y)-5(X+Y)²
=3(X+Y)²+2(X+Y)²-5(X+Y)²-(X-Y)+(X-Y)
=0

全都抵消了,等于零