∫1/((x²-1)(x²+1))dx求高手解答!∫1/((x²-1)(x²+1))dx（2）∫1/x²(1+x²)dx

∫1/((x²-1)(x²+1))dx求高手解答!∫1/((x²-1)(x²+1))dx（2）∫1/x²(1+x²)dx
∫1/((x²-1)(x²+1))dx求高手解答!
∫1/((x²-1)(x²+1))dx
（2）∫1/x²(1+x²)dx

∫1/((x²-1)(x²+1))dx求高手解答!∫1/((x²-1)(x²+1))dx（2）∫1/x²(1+x²)dx
（1）原式=∫1/2（1/（x^2-1）-1/(x^2+1))dx=1/2∫1/2(1/(x-1)-1/(x+1))dx-1/2∫1/(x^2+1)dx
=1/4ln(x-1)/(x+1)-1/2arctanx
(2)原式=∫（1/x^2-1/(1+x^2)）dx=-1/x-arctanx
原来以为两个题,结果,你妹啊
这些都很简单,自己做