two person are running towards each other.they are 37m apart.if one is accelerating from rest at 0.5m/s^2 and the other was a;ready moving at 3.1m/s and maintains herspeed.a)how long before they crunch togetherb) how fast was the accelerating player

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twopersonarerunningtowardseachother.theyare37mapart.ifoneisacceleratingfromrestat0.5m/s^2andtheother

two person are running towards each other.they are 37m apart.if one is accelerating from rest at 0.5m/s^2 and the other was a;ready moving at 3.1m/s and maintains herspeed.a)how long before they crunch togetherb) how fast was the accelerating player
two person are running towards each other.they are 37m apart.if one is accelerating from rest at 0.5m/s^2 and the other was a;ready moving at 3.1m/s and maintains herspeed.
a)how long before they crunch together
b) how fast was the accelerating player going
c)how far has each person run
咱不需要翻译只要解题~
如有不明或需要翻译这题可以跟我说
两个人都奔向对方。他们的距离是37米。如果一个人从静止加速在0.5米/秒^ 另一个是，一直移动3.1米/秒，并保持他的速度。
a）他们是什么时候碰在一起
b）加速的人的速度是什么
c）两个人分别跑了多少

two person are running towards each other.they are 37m apart.if one is accelerating from rest at 0.5m/s^2 and the other was a;ready moving at 3.1m/s and maintains herspeed.a)how long before they crunch togetherb) how fast was the accelerating player
a) 1/2 *0.5*t^2 + 3.1*t = 37
t = 7.4543 s
b) v = 0.5* 7.4543 = 3.72715 m/s
c) 1/2 *0.5*t^2 = 1/2 *0.5*7.4543 ^2 = 13.8916 m
3.1*t = 3.1* 7.4543 = 23.1083 m

也许我能答这题，可你要先翻译好，哈哈。

解
A 假设他们是在t秒后碰在一起则t秒后2人运动的路程加起来是37米即
（1/2）at²+Ut=37=1/2 *0.5*t^2 + 3.1*t 解得 t = 7.4543 s
B加速人的速度。加速度是a 时间是t 有公式U=at得U=0.5* 7.4543 =3.72715 m/s
C就是A中的2个位移 1个是X=（1/2）at&s...

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解
A 假设他们是在t秒后碰在一起则t秒后2人运动的路程加起来是37米即
（1/2）at²+Ut=37=1/2 *0.5*t^2 + 3.1*t 解得 t = 7.4543 s
B加速人的速度。加速度是a 时间是t 有公式U=at得U=0.5* 7.4543 =3.72715 m/s
C就是A中的2个位移 1个是X=（1/2）at²= 1/2 *0.5*7.4543 ^2 = 13.8916 m
1个是X=Ut=3.1* 7.4543 = 23.1083 m
他们两个加起来是37m

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