矩形周长16,两边分别为x.y,满足4x-4y-x²+2xy-y²-4=0 求该矩形面积
来源:学生作业帮助网 编辑:六六作业网 时间:2024/12/23 03:34:36
矩形周长16,两边分别为x.y,满足4x-4y-x²+2xy-y²-4=0求该矩形面积矩形周长16,两边分别为x.y,满足4x-4y-x²+2xy-y²-4=0
矩形周长16,两边分别为x.y,满足4x-4y-x²+2xy-y²-4=0 求该矩形面积
矩形周长16,两边分别为x.y,满足4x-4y-x²+2xy-y²-4=0 求该矩形面积
矩形周长16,两边分别为x.y,满足4x-4y-x²+2xy-y²-4=0 求该矩形面积
4x-4y-x²+2xy-y²-4=0
4(x-y)-(x-y)² -4=0
(x-y)²-4(x-y)-4=0
(x-y-2)²=0
x-y=2因为x+y=8
所以x y分别为5和3
所以面积为15
4x-4y-x²+2xy-y²-4=0
4(x-y)-(x²-2xy+y²)-4=0
4(x-y)-(x-y)²-4=0
(x-y)²-4(x-y)+4=0
(x-y-2)²=0
x-y=2
2*(x+y)=16
x+y=8
列方程组:
得出x=5
y=3
S=3*5=15