将函数y=sin(7π/8-x)cos(x+π/8)的化简

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将函数y=sin(7π/8-x)cos(x+π/8)的化简将函数y=sin(7π/8-x)cos(x+π/8)的化简将函数y=sin(7π/8-x)cos(x+π/8)的化简原式=sin[π-(7π/

将函数y=sin(7π/8-x)cos(x+π/8)的化简
将函数y=sin(7π/8-x)cos(x+π/8)的化简

将函数y=sin(7π/8-x)cos(x+π/8)的化简
原式=sin[π-(7π/8-x)]cos(x+π/8)
=sin(x+π/8)cos(x+π/8)
=1/2[2sin(x+π/8)cos(x+π/8)]
=1/2sin[2(x+π/8)]
=(1/2)sin(2x+π/4)