设函数y=sin(x^2-1),则dy=
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设函数y=sin(x^2-1),则dy=设函数y=sin(x^2-1),则dy=设函数y=sin(x^2-1),则dy=dy=cos(x^2-1)(x^2-1)''dx=cos(x^2-1)*2xdx=
设函数y=sin(x^2-1),则dy=
设函数y=sin(x^2-1),则dy=
设函数y=sin(x^2-1),则dy=
dy=
cos(x^2-1)(x^2-1)'dx
=cos(x^2-1)*2xdx
=2xcos(x^2-1)dx
2xcos(x^2-1)dx
y=f(u)=sinu
u=x^2-1
所以dy=f'(u)*u'dx=cosu*2xdx=2xcos(x^2-1)dx