√x^2+y^2/√(x-3)^2+y^2=1/2 如何化简成曲线方程：x^2+y^2+2x-3=0（√是根号）√x^2+y^2/√(x-3)^2+y^2=1/2 如何化简成曲线方程：x^2+y^2+2x-3=0

先化简 再求值 (2x-y)(y+x)-(x-2y)(2y+x)-(-3y+x)^2其(√x+1)+y^2+4=-4y x(x-y)2-(y-x)3 [2/3x-2/x+y(x+y/3x-x-y)]/x-y/x 化简：{2/3x-2/(x+y)[(x+y)/3x-x-y]}/(x+y)/x 计算2/3x-2/x+y(x+y/3x-x-y)/x-y/x 化简3x-2/(x+y)[(x+y)/3x-x-y]÷(x-y)/x y^2-2(√x+1/√x)y+3 若x>0,y>0,且√x(√x+√y)=3√y(√x+5√y),求2x+2√x*√y+3y/x-√x*√y+y x-y/x-x+y/y-(x+y)(x-y)/y² y/x=2 计算：x+2y/x-y+2x/y-x-3y/x-y 化简:(x-3y)(x+y)-(x-2y)(x+2y)-(x-y)平方 [(3x+y)(x-y)-(2x+3y)(x-y)]*(x-y) 已知√(y/x)+√(x/y)=3√2/2,那么y/x+x/y的值为 若x,y∈{-√3,-1,1,2},则(x,y)∈{(x,y)|x^2+y^2 √x+y-3+/xy+x+y-2/＝0,求x÷y+y÷x的值. ³√x+y=3,√x-y=2 求x,y的平方根 |2x+y+1|+√2y+3x=0则x.y= |x-2y|+√3x-4y =0求x y值