2X+Y=3 3X-5Y=11
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2X+Y=33X-5Y=112X+Y=33X-5Y=112X+Y=33X-5Y=11由第一个式子得到Y=3-2X,代入第二个式子3X-5(3-2X)=1113X=26X=2所以Y=-12X+Y=3的左
2X+Y=3 3X-5Y=11
2X+Y=3 3X-5Y=11
2X+Y=3 3X-5Y=11
由第一个式子得到Y=3-2X,代入第二个式子
3X-5(3-2X)=11
13X=26
X=2
所以Y=-1
2X+Y=3的左右两边乘5,然后将此等式与第二个等式:3X-5Y=11相加;抵消了Y,只乘一个变量:Y;即可求得X=2;Y=-1;
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