(1-i)[sin^2 (x/2)+isin^2(x/2)]+isin(x) 求复数的值,并写出三角和指数表达式 要详细步骤
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(1-i)[sin^2(x/2)+isin^2(x/2)]+isin(x)求复数的值,并写出三角和指数表达式要详细步骤(1-i)[sin^2(x/2)+isin^2(x/2)]+isin(x)求复数的
(1-i)[sin^2 (x/2)+isin^2(x/2)]+isin(x) 求复数的值,并写出三角和指数表达式 要详细步骤
(1-i)[sin^2 (x/2)+isin^2(x/2)]+isin(x) 求复数的值,并写出三角和指数表达式 要详细步骤
(1-i)[sin^2 (x/2)+isin^2(x/2)]+isin(x) 求复数的值,并写出三角和指数表达式 要详细步骤
个人认为:1、化为1-cosx+isinx 后就无法得出三角表示式和指数表达式.
2、把isin(x)用正弦二倍角公式分解得:2isin(x/2)cos(x/2),之后再提取2sin(x/2).
3、得2sin(x/2)[icos(x/2)+sin(x/2)],再把cos和sin调换.得出:2sin(x/2)[cos(П/2-x/2)+isin(П/2-x/2)]
4、最后用欧拉公式得指数表达式
(1-i)e*sin^(x/2)+isin(x)
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