2sin²12分之7π-1=
来源:学生作业帮助网 编辑:六六作业网 时间:2024/12/22 15:51:01
2sin²12分之7π-1=2sin²12分之7π-1=2sin²12分之7π-1=2sin²7π/12-1=-(1-2sin²7π/12)=-cos
2sin²12分之7π-1=
2sin²12分之7π-1=
2sin²12分之7π-1=
2sin²7π/12-1
=-(1-2sin²7π/12)
=-cos7π/6
=-cos(π+π/6)
=cosπ/6=根号3/2