已知4x²+y²-4x-6y+10=0,求(2/3√9x+y²√x/y³)-(x√1/x-5x√y/x)的值.

已知4x²+y²-4x-6y+10=0,求(2/3√9x+y²√x/y³)-(x√1/x-5x√y/x)的值.
已知4x²+y²-4x-6y+10=0,求(2/3√9x+y²√x/y³)-(x√1/x-5x√y/x)的值.

已知4x²+y²-4x-6y+10=0,求(2/3√9x+y²√x/y³)-(x√1/x-5x√y/x)的值.
4x^2+y^2-4x-6y+10=0.
配方得(2x-1)^2+(y-3)^2=0,
∴2x-1=0,y-3=0,
解得x=1/2,y=3.
∴(2/3)√(9x)+y^2√(x/y^3)-[x√(1/x)-5x√(y/x)]
=√2+√6/2-[√2/2-(5/2)√6]
=（3/2）√2+3√6.