x²-12/x﹙x-2﹚=2x-1
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x²-12/x﹙x-2﹚=2x-1x²-12/x﹙x-2﹚=2x-1x²-12/x﹙x-2﹚=2x-1x^2-2x+1=12/(x^2-2x)令x^2-2x=t(t>=-
x²-12/x﹙x-2﹚=2x-1
x²-12/x﹙x-2﹚=2x-1
x²-12/x﹙x-2﹚=2x-1
x^2-2x+1=12/(x^2-2x)
令x^2-2x=t(t>=-1)
所以t+1=12/t
所以t=3或-4(舍)
所以x^2-2x=3
x=3或-1
∵×2-5X-1997 = 0
∴×2-5X = 1997
[(X-2)^ 3 - (X-1)2 +1] /(X- 2)
=(X 3-6×2 12 X-8-X 2 2 x-1的1)/(X-2)
=(X 3-7X 2 14的x 8)/(X-2)
=(×3 -8) - (7倍2-14X)/(X-2)
= [(X-2)(X 2 2...
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∵×2-5X-1997 = 0
∴×2-5X = 1997
[(X-2)^ 3 - (X-1)2 +1] /(X- 2)
=(X 3-6×2 12 X-8-X 2 2 x-1的1)/(X-2)
=(X 3-7X 2 14的x 8)/(X-2)
=(×3 -8) - (7倍2-14X)/(X-2)
= [(X-2)(X 2 2 X + 4)-7X(X-2)] /(X-2)
=(X-2)(X 2 2的X 7倍4)/(X-2)
=×2 -5X +4
= 1997 +4
= 2001
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