(1/x+1/6)×1.2=1/2
来源：学生作业帮助网 编辑：六六作业网 时间：2024/12/18 11:43:57
(1/x+1/6)×1.2=1/2(1/x+1/6)×1.2=1/2(1/x+1/6)×1.2=1/21.2/x+1.2/6=1/21.2/x+0.2=0.51.2/x=0.3x=1.2/0.3=4
(1/x+1/6)×1.2=1/2
(1/x+1/6)×1.2=1/2
(1/x+1/6)×1.2=1/2
1.2/x+1.2/6=1/2
1.2/x+0.2=0.5
1.2/x=0.3
x=1.2/0.3=4
x/x-2+x-9/x-7=x+1/x-1+x-8/x-6,
x/x-2+x-9/x-7=x+1/x-1+x-8/x-6,
*-----------------------------------------------*| 6 4 X | 8 X X | X X 5 || X X X | X X X | X 7 8 || X X X | X X X | X X X ||---------------+---------------+--------------- || X X X | X X X | 5 1 X || X X X | X 6 X | X X X || 8 X X | 3 5 X | 2 X X ||
填九宫格帮帮忙.x x 6 x x 7 x x 98 x x x 3 x 1 x x 9 x x 6 x 5 x 3 x x x 3 x x x x 1 8x x x 9 x 1 x x x2 1 x x x x 6 x x x 6 x 7 x 3 x x 1 x x 9 x 2 x x x 47 x x 8 x x 5 x x
解方程x/(x-2)=2x/(x-3)+(1-x)/(x-5x+6)
(x/x-2)+(2/x*2+2x)-(x+6/x*2-4)化简,=x^2/x(x-2)+(2x-4)/x(x^2-4)-(x^2+6x)/x(x^2-4)=x^2/x(x-2)-(x+2)/x(x-2)=(x-2)(x+1)/x(x-2)=(x+1)/x
x+2/x+1-x+4/x+3=x+6/x+5-x+8/x+7 x=?
1.用公式计算：COSX=1-X*X/2!X*X*X*X/4!-X*X*X*X*X*X/6!.直到最后一项的绝对
6/(x-1)-(x+2)/x(x-1)=0
(x+7)(x+6)-(x-2)(x+1)=?
(x+2)(x-3)(x-6)(x-1)=0
1/x-2 +3 =1-x/2-x 3/x + 6/x-1=x+5/x²-x
3X*X-2X+6=8,X=?3X*X-2X+6=8，X=？则代数式1.5X*X-X+1=?
解方程(x-6)(x^2+x+1)-x(x+1)(x-1)=x(2-5x)
已知x=2π+1求 |x-1|+|x-2|+|x-3|+|x-4|+|x-5|+|x-6|+|x-7|+|x-8|+|x-9|+|x-10|
x+1/x=6,则x^2+1/x^2=,(x-1/x)^2
4x/(x²-4)-（2x+6)/(x²+x-6)=1-(x-3)/(x²-x-6)
分式方程.x/(x-2)+(x-9)/(x-7)=(x+1)/(x-1)+(x-8)/(x-6)