(2x-y)/3 = (x+3y)/5 =2 求x、y

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(2x-y)/3=(x+3y)/5=2求x、y(2x-y)/3=(x+3y)/5=2求x、y(2x-y)/3=(x+3y)/5=2求x、y解(2x-y)/3=2(x+3y)/5=2即2x-y=6①x+

(2x-y)/3 = (x+3y)/5 =2 求x、y
(2x-y)/3 = (x+3y)/5 =2 求x、y

(2x-y)/3 = (x+3y)/5 =2 求x、y
解
(2x-y)/3=2
(x+3y)/5=2
即
2x-y=6 ①
x+3y=10 ②
①×3得：6x-3y=18 ③
③+②得：
7x=28
∴x=4,y=2

答：
(2x-y)/3 = (x+3y)/5 =2
则有：2x-y=6，y=2x-6
x+3y=10
所以：x+3(2x-6)=10
x+6x-18=10
7x=28
x=4
代入y=2x-6得：y=2
所以：x=4，y=2

(2x-y)/3=2
(x+3y)/5=2
(1式)2x-y=6
(2式)x+3y=10
把y=2x-6代入（2式）得x=4
把4代入(1式)得y=2

就是个二元一次方程，x=4；y=2

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