1/(3*5)+1/(5*7)+1/(7*9)+…1/(103*105)分子都是1,括号内的两数是分母!
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1/(3*5)+1/(5*7)+1/(7*9)+…1/(103*105)分子都是1,括号内的两数是分母!1/(3*5)+1/(5*7)+1/(7*9)+…1/(103*105)分子都是1,括号内的两数
1/(3*5)+1/(5*7)+1/(7*9)+…1/(103*105)分子都是1,括号内的两数是分母!
1/(3*5)+1/(5*7)+1/(7*9)+…1/(103*105)
分子都是1,括号内的两数是分母!
1/(3*5)+1/(5*7)+1/(7*9)+…1/(103*105)分子都是1,括号内的两数是分母!
1/(3*5)+1/(5*7)+1/(7*9)+…1/(103*105)
=1/2*(1/3-1/5+1/5-1/7+1/7+...-1/103+1/103-1/105)
=1/2*(1/3-1/105)
=17/105
简便运算 (1+1/3+1/5+1/7)*(1/3+1/5+1/7+1/9)-(1+1/3+1/5+1/7+1/7+1/9)*(1/3+1/5+1/7)
算术题,(1+1/3+1/5+1/7)×(1/3+1/5+1/7+1/9)-(1+1/3+1/5+1/7+1/9)×(1/3+1/5+1/7)
数奥题(1+1/3+1/5+1/7)*(1/3+1/5+1/7+1/9)-(1+1/3+1/5+1/7+1/9)*(1/3+1/5+1/7)求(1+1/3+1/5+1/7)*(1/3+1/5+1/7+1/9)-(1+1/3+1/5+1/7+1/9)*(1/3+1/5+1/7)的简便算法要求:
(-5)*(+7 1/3)+(+7)*(-7 1/3)-(+12)*7 1/3 简便方法计算
两题算24点.1、(7、7、3、3)2、(5、5、5、1)
计算 (1)(1-105×(3/1-7/3-7/5-5/2)怎么算的 式子 105×(3/1-7/3-7/5-5/2)
1/(1×3×5)+1/(3×5×7)+1/(5×7×9)+1/(7×9×11)+...+1/(2001×2003×2005)=?
(4/5+1/4)÷7/3+7/10
1/(1*3*5)+1/(3*5*7)+1/(5*7*9)+1/(7*9*11).+(25*27*29)
简算 (2+3+1/5)+(2/3-5/17)-(1/5+12/7)
1/(1*3)+1/(3*5)+1/(5*7)+1/(7*9)...1/(199*201)=?
计算:(- 1/7)+3/5+4/7+(- 1/5)
1+3+5= 1+3+5+7= 1+3+5+7+.+(2n-1)=
1/1*3=1/2(1-1/3)1/3*5=1/2(1/3-1/5)1/5*7=1/2(1/5-1/7).1/17*19=1/2(1/17-1/19)所以1/1*3+1/3*5+1/5*7+.1/17*19=1/2(1-1/3)+1/2(1/3+1/5)+1/2(1/5-1/7)+.1/2(1/17-1/19)=1/2(1-1/3+1/3-1/5+1/5-1/7+1/7.+1/17-1/19)=1/2(1-1/1
找规律1,2,3,5,8,()()7,8,6,7,5,()()
-0.25/(-3/7)x(3/7)x(-1-1/5)
【(1+1/7)-(-3)+(-1/5)】/(-1/105)
(1/8+2/8+3/8)+(1/5+1/7)-(1/5乘1/7)乘(35除以7乘5)=