（1/x-y-1/x+y）÷2y/x²-2xy+y²,其中x=√2+1,y=1-√2
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（1/x-y-1/x+y）÷2y/x²-2xy+y²,其中x=√2+1,y=1-√2（1/x-y-1/x+y）÷2y/x²-2xy+y²,其中x=√2+1,y=
（1/x-y-1/x+y）÷2y/x²-2xy+y²,其中x=√2+1,y=1-√2
（1/x-y-1/x+y）÷2y/x²-2xy+y²,其中x=√2+1,y=1-√2
（1/x-y-1/x+y）÷2y/x²-2xy+y²,其中x=√2+1,y=1-√2
（1/x-y-1/x+y）÷2y/x²-2xy+y²
=2y/(x²-y²)÷2y/(x-y)²
=(x-y)/(x+y)
=2y/(x^2-y^2) / 2y/(x-y)^2=(x-y)^2 / [(x-y)*(x+y)] = 8/ 4√2= √2