计算2x(3+10x(3^2+1)x(3^4+1)x...x(3^32+1)+1
来源：学生作业帮助网 编辑：六六作业网 时间：2024/11/17 13:56:42
计算2x(3+10x(3^2+1)x(3^4+1)x...x(3^32+1)+1计算2x(3+10x(3^2+1)x(3^4+1)x...x(3^32+1)+1计算2x(3+10x(3^2+1)x(3
计算2x(3+10x(3^2+1)x(3^4+1)x...x(3^32+1)+1
计算2x(3+10x(3^2+1)x(3^4+1)x...x(3^32+1)+1
计算2x(3+10x(3^2+1)x(3^4+1)x...x(3^32+1)+1
2x(3+10x(3^2+1)x(3^4+1)x...x(3^32+1)+1
=(3-1)(3+1)(3^2+1).(3^32+1)+1
=(3^2-1)(3^2+1).(3^32+1)+1
=.
=3^64-1+1
=3^64
祝开心
哈哈，坐等数学帝，你没分啊
2x(3+1)x(3^2+1)x(3^4+1)x...x(3^32+1)+1
=(3-1)x(3+1)x(3^2+1)x(3^4+1)x...x(3^32+1)+1
=(3²-1)x(3^2+1)x(3^4+1)x...x(3^32+1)+1
=(3^4-1)x(3^4+1)x...x(3^32+1)+1
=(3^32-1)x(3^32+1)+1
=(3^64-1)+1
=3^64
如何计算（x-1)(x-2)(x-3)(x-4)-(x^2-5x)^2-10(x^2-5x)
计算（x*x+4x+5）/（x+2）-（x*x+6x+10）/（x+3）+1
计算(x+1)(x+2)(x+3)(x+4)
计算：（x+1)(x-2)(x-3)(x-6)
计算 x(x+3)-(x-1)(x-2）
如何计算 (x+1)(x+2)(x+3)(x+4)
计算(X-1)(X-2)(X-3)(X-4)
(x-1)(x-2)(x-3)(x-4)-24计算
计算：x/(x-1)-(x+3)/(x^-1)*(x^2+2x+1)/(x+3)
计算:[(x^2 - 4)/(x^2 - x - 6) + (x+2)/(x-3)] / (x+1)/(x-3)
计算：1-2x+x^2/x-x^3*xy+x^2y/x-x^2
x/x-3-5x/x^2-x-6计算
x(x-2)(2x-3)计算
计算： (x+3)(x²-x-2)
计算 (x+3)(x²-x-2)
2x*4x-3x计算
计算:x/x-2 - 5x/x²-x-6计算:x/x-3 - 5x/x²-x-6
计算10/(x^3-2x^2+x)-(x+1)/(x-1)+1