(x^2-2x+1)/(x^2-1)除以[1+(x+3)/(x+1)]化简

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(x^2-2x+1)/(x^2-1)除以[1+(x+3)/(x+1)]化简(x^2-2x+1)/(x^2-1)除以[1+(x+3)/(x+1)]化简(x^2-2x+1)/(x^2-1)除以[1+(x+

(x^2-2x+1)/(x^2-1)除以[1+(x+3)/(x+1)]化简
(x^2-2x+1)/(x^2-1)除以[1+(x+3)/(x+1)]化简

(x^2-2x+1)/(x^2-1)除以[1+(x+3)/(x+1)]化简
我分开来写吧
(x²-2x+1)/(x²-1)
=(x-1)²/(x-1)(x+1)
=(x-1)/(x+1)
1+(x+3)/(x+1)=(2x+4)/(x+1)
∴原式=(x-1)/2(x+2)
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=(x-1)²/(x-1)(x+1)÷(x+1+x+3)/(x+1)
=(x-1)/(x+1)×(x+1)/(2x+4)
=(x-1)/(2x+4)