[a(m+n)-2b(m+n)]÷(m+n)和[3x(y-z)+(y-z)]÷(y-z)和[2x²(x-3)-5(x-3)]÷(x-3)和[(2x+y)(2x-y)-(2x+y)]÷(22+y)用分解因式的办法计算

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[a(m+n)-2b(m+n)]÷(m+n)和[3x(y-z)+(y-z)]÷(y-z)和[2x²(x-3)-5(x-3)]÷(x-3)和[(2x+y)(2x-y)-(2x+y)]÷(22+

[a(m+n)-2b(m+n)]÷(m+n)和[3x(y-z)+(y-z)]÷(y-z)和[2x²(x-3)-5(x-3)]÷(x-3)和[(2x+y)(2x-y)-(2x+y)]÷(22+y)用分解因式的办法计算
[a(m+n)-2b(m+n)]÷(m+n)和[3x(y-z)+(y-z)]÷(y-z)和[2x²(x-3)-5(x-3)]÷(x-3)和[(2x+y)(2x-y)-(2x+y)]÷(22+y)用分解因式的办法计算

[a(m+n)-2b(m+n)]÷(m+n)和[3x(y-z)+(y-z)]÷(y-z)和[2x²(x-3)-5(x-3)]÷(x-3)和[(2x+y)(2x-y)-(2x+y)]÷(22+y)用分解因式的办法计算
[a(m+n)-2b(m+n)]÷(m+n)
=(a-2b)(m+n)÷(m+n)
=a-2b;
[3x(y-z)+(y-z)]÷(y-z)
=(3x+1)(y-z)÷(y-z)
=3x+1;
[2x²(x-3)-5(x-3)]÷(x-3)
=(2x²-5)(x-3)÷(x-3)
=2x²-5;
[(2x+y)(2x-y)-(2x+y)]÷(22+y
=(2x+y)(2x-y-1)÷(2x+y)
=2x-y-1;
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