已知x+2y+3z=54,3x+2y+2z=47,2x+y+z=31,求代数式x+y+z的值

已知x+2y+3z=54,3x+2y+2z=47,2x+y+z=31,求代数式x+y+z的值
已知x+2y+3z=54,3x+2y+2z=47,2x+y+z=31,求代数式x+y+z的值

已知x+2y+3z=54,3x+2y+2z=47,2x+y+z=31,求代数式x+y+z的值
不会是解方程那么复杂,请确定下第三个式子y的系数是1还是2
如果是2的话,三式相加你就看出来了

将三个式子左右同时相加得6x+6y+6z=132
得x+y+z=132/6=22

x+2y+3z=54 1
3x+2y+2z=47 2
2x+y+z=31 3
2-3,x+y+z=16