3x+2y+z=6 2x+y+3z=1 x+3y+2z=53x+2y+z=62x+y+3z=1 x+3y+2z=5解方程组
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3x+2y+z=62x+y+3z=1x+3y+2z=53x+2y+z=62x+y+3z=1x+3y+2z=5解方程组3x+2y+z=62x+y+3z=1x+3y+2z=53x+2y+z=62x+y+3
3x+2y+z=6 2x+y+3z=1 x+3y+2z=53x+2y+z=62x+y+3z=1 x+3y+2z=5解方程组
3x+2y+z=6 2x+y+3z=1 x+3y+2z=5
3x+2y+z=6
2x+y+3z=1
x+3y+2z=5
解方程组
3x+2y+z=6 2x+y+3z=1 x+3y+2z=53x+2y+z=62x+y+3z=1 x+3y+2z=5解方程组
3x+2y+z=6为a式
2x+y+3z=1为b式
x+3y+2z=5为c式
由c得,x=5-3y-2z为d式
把d代入a和b式中,得3(5-3y-2z)+2y+z=6作为a*式和2(5-3y-2z)+y+3z=1作为b*
展开得:15-9y-6z+2y+z=6和10-6y-4z+y+3z=1
于是得出:a*式变得7y+5z=9,b*式变得5y+z=-9
b*式乘以5得到:25y+5z=-45
b*-a*得:18y=-54即 y=-3
把y=-3代入b*中得:z=6
把y和z的值代入最先变的d式中,得到x=2
x+y+z=6 x+2y+3z=14 y+1=z
试证明(x+y-2z)+(y+z-2x)+(z+x-2y)=3(x+y-2z)(y+z-2x)(z+x-2y)
已知(x+y)(x+z)=x,(y+z)(y+x)=2y,(z+x)(z+y)=3z,求x,y,z
已知实数x y z满足x/(x+1)=y/(y+2)=z/(z+3)=(x+y+z)/3,求x+y+z的值
已知实数x y z满足x/(x+1)=y/(y+2)=z/(z+3)=(x+y+z)/3,求x+y+z的值
(1)X+Y=15,Y+Z=-6,Z+X=7.(2)X+Y=-14,Y+Z=-7,Z+X=9.(3)X+Y=0,Y+Z=-1,Z+X=-1.
若|x+3|+|y-2|+|2×z+1|=0求(x×z-y×z)(y-x+z)的值
x=2y-9z x+2y-3z=2 x-2y+6z=1
x+y-z=6 x-3y+2z=1 3x+2y-z=4 阿
x+y-z=6,x-3y+2z=1,3x+2y-z=4
x+y-z=6 x-3y+2z=1 3x+2y-z=4
x+y-z=6 x-3y+2z=1 3x+y-z=4
x-y+z=-1 5x+2y-z=6 4x-3y+2z=-5
x+y+z=1 4x+5y-z=6 x+2y-z=3
1.{x:y:z=3:4:5 2x+3y-5z=-142.{x-y-z=-1 3x+5y+7z=11 4x-y+2z=-13.{x+y=1 x+z=0 2x+y+2z=44.{x-y+z=-3 2x-y-z=-2 -3x+y+z=-15.{x-y+z=-3 3x+y-4z=6 2x+y-z=36.{x-2y+5z=16 2x+y-5z=7 2x-y+z=38
matlab解对数方程组[x,y,z]=solve('0.29744*x/(3+0.1*x+y+z)=(log10((3+x+y+z)/(3+0.1*x+y+z)))^2','0.79*x/(3+0.1*y+z)=(log10((3+x+y+z)/(3+0.1*x+y+z)*(3+y+z)/(3+0.1*y+z)))^2','1.25*x/(3+0.1*z)=(log10((3+x+y+z)/(3+0.1*x+y+z)*(3+y+z)/(3+0.*1y+z)*(3+z)/
如果|x+y+z-6|+|2x+3y-z-12|+|2x-y-z|=0求x,y,
x+y-z=6(1) x-3y+2z=1(2) 3x+2y-z=4(3) 求X Y Z 的值