=lime^[(a^xlna+b^xlnb+c^xlnc)/3]=[e^(lna+lnb+lnc)]^1/3求解这一步是怎么来的………

来源:学生作业帮助网 编辑:六六作业网 时间:2024/11/23 20:38:45
=lime^[(a^xlna+b^xlnb+c^xlnc)/3]=[e^(lna+lnb+lnc)]^1/3求解这一步是怎么来的………=lime^[(a^xlna+b^xlnb+c^xlnc)/3]=

=lime^[(a^xlna+b^xlnb+c^xlnc)/3]=[e^(lna+lnb+lnc)]^1/3求解这一步是怎么来的………
=lime^[(a^xlna+b^xlnb+c^xlnc)/3]
=[e^(lna+lnb+lnc)]^1/3
求解这一步是怎么来的………

=lime^[(a^xlna+b^xlnb+c^xlnc)/3]=[e^(lna+lnb+lnc)]^1/3求解这一步是怎么来的………
令y=e^(a^xlna+b^xlnb+c^xlnc)/3
那么lny=(a^xlna+b^xlnb+c^xlnc)/3
两边取极限的
lim(lny)=(lna+lnb+lnc)/3
而且原来的极限
=lim(e^lny)=e^(limlny)=e^[(lna+lnb+lnc)/3]=[e^(lna+lnb+lnc)]^1/3