若x²-y²=1且x＞0,y＞0,求x√(1+y²)-y√(x²-1)的值

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若x²-y²=1且x＞0,y＞0,求x√(1+y²)-y√(x²-1)的值若x²-y²=1且x＞0,y＞0,求x√(1+y²)-y

若x²-y²=1且x＞0,y＞0,求x√(1+y²)-y√(x²-1)的值
若x²-y²=1且x＞0,y＞0,求x√(1+y²)-y√(x²-1)的值

若x²-y²=1且x＞0,y＞0,求x√(1+y²)-y√(x²-1)的值
答案是1